A wire of resistance 10 Ω is stretched to double its length. Its new resistance is MCQ with Answer and Explanation

A wire of resistance 10 Ω is stretched to double its length. Its new resistance is
A. 10 Ω
B. 5 Ω
C. 40 Ω
D. 20 Ω
Answer: Option C
Solution (By JKExamLibrary)
Resistance R = ρL/A. Volume constant: A ∝ 1/L. Stretching length to 2L reduces area to A/2. New R' = ρ(2L)/(A/2) = 4ρL/A = 4R = 40 Ω. Resistance proportional to (length)² when volume constant.

This question belongs to: Science Physics

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