A wire of resistance 10 Ω is stretched to double its length. Its new resistance is
A. 10 Ω
B. 5 Ω
C. 40 Ω
D. 20 Ω
Answer: Option C
Solution (By JKExamLibrary)
Resistance R = ρL/A. Volume constant: A ∝ 1/L. Stretching length to 2L reduces area to A/2. New R' = ρ(2L)/(A/2) = 4ρL/A = 4R = 40 Ω. Resistance proportional to (length)² when volume constant.
Explanation:
Weight = mg = 10×10 = 100 N. In free fall, only force is gravity (air resistance neglected). Net force = weight, so F = 100 N, causing acceleration g.
Explanation:
A Miniature Circuit Breaker (MCB) serves the same safety function as a fuse: breaking the circuit during an overload or short circuit. However, unlike a fuse wire that melts and must be physically replaced, an MCB contains an electromechanical mechanism that trips the switch. It can simply be switched back on to restore power.
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