Statistics MCQs

Accountancy and Statistics

Statistics MCQs

Practice complete Statistics MCQs covering Primary & Secondary Data, Data Collection Methods, Questionnaire, Tabulation & Compilation of Data, Measures of Central Tendency, Probability, Theory of Attributes, Index Numbers, Demography, Census, Vital Statistics, Fertility Measures, and all other important topics. Includes chapter-wise and exam-oriented multiple choice questions with detailed answers and explanations for JKSSB, SSC, Banking, UPSC, CUET, University, and other competitive exams.

1318
Total Questions

Practice Questions

Page 19 of 66
Question #361
A frequency distribution has classes 0-10, 10-20, 20-30, 30-40. The median class is 20-30 and the cumulative frequency before this class is 30. If N=80, frequency of median class is 20. The median is:
A. 23
B. 26
C. 24
D. 25
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
Median = L + (N/2 - cf)/f × h = 20 + (40-30)/20 × 10 = 20 + 10/20×10 = 20 + 5 = 25.
This question belongs to: Accountancy and Statistics Statistics
Question #362
In a distribution, the mode is 30, median 32, mean 34. The distribution is:
A. Leptokurtic
B. Negatively skewed
C. Symmetric
D. Positively skewed
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
Mean > Median > Mode indicates positive skewness.
This question belongs to: Accountancy and Statistics Statistics
Question #363
For a symmetric distribution, which statement is correct?
A. Mean - Mode = 3(Mean - Median)
B. Median = (Mean + Mode)/2
C. Mode = 3Median - 2Mean
D. Mean = Median = Mode
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
In a perfectly symmetric distribution, all three central measures coincide.
This question belongs to: Accountancy and Statistics Statistics
Question #364
In a set of 10 numbers, the mean of the first 6 is 15 and the mean of the remaining 4 is 20. The combined mean is:
A. 17.5
B. 18
C. 16.5
D. 17
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
Sum = 6×15 + 4×20 = 90+80=170. Combined mean = 170/10 = 17.
This question belongs to: Accountancy and Statistics Statistics
Question #365
Which measure of central tendency is undefined for data containing zero?
A. Arithmetic mean
B. Geometric mean
C. Median
D. Harmonic mean
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
Harmonic mean involves reciprocals; if any value is zero, reciprocal is infinite, so it's undefined.
This question belongs to: Accountancy and Statistics Statistics
Question #366
The sample space for tossing two coins simultaneously is:
A. {HH,HT,TH,TT}
B. {H,T}
C. {HH,HT,TT}
D. {0,1,2}
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option A

Explanation:
Two independent outcomes for each coin yield four ordered pairs.
This question belongs to: Accountancy and Statistics Statistics
Question #367
If P(A)=0.35, P(B)=0.55, and P(A∩B)=0.20, then P(A'∩B') is:
A. 0.80
B. 0.30
C. 0.70
D. 0.10
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option B

Explanation:
P(A∪B)=0.35+0.55-0.20=0.70. P(A'∩B') = 1 - 0.70 = 0.30.
This question belongs to: Accountancy and Statistics Statistics
Question #368
A speaks truth in 70% cases, B in 80% cases. In what percentage of cases are they likely to contradict each other in stating the same fact?
A. 56%
B. 44%
C. 38%
D. 50%
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option C

Explanation:
Contradiction = P(A truth and B lie) + P(A lie and B truth) = 0.7×0.2 + 0.3×0.8 = 0.14+0.24=0.38=38%.
This question belongs to: Accountancy and Statistics Statistics
Question #369
Three students A,B,C solve a problem. Probabilities 1/2, 2/3, 3/4. Probability that exactly two of them solve it is:
A. 1/4
B. 7/24
C. 11/24
D. 13/24
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option C

Explanation:
P(AB'C) = 1/2 * 1/3 * 3/4 = 3/24; P(AB'C)? Let's compute exactly two: A and B not C: 1/2*2/3*1/4=2/24; A not B C: 1/2*1/3*3/4=3/24; not A B C: 1/2*2/3*3/4=6/24. Sum = 11/24.
This question belongs to: Accountancy and Statistics Statistics
Question #370
A card is drawn from a well-shuffled deck of 52 cards. The probability that it is a jack or a spade is:
A. 16/52
B. 1/4
C. 4/13
D. 17/52
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option A

Explanation:
P(jack)=4/52, spade=13/52, jack of spades=1/52. P=4/52+13/52-1/52=16/52.
This question belongs to: Accountancy and Statistics Statistics
Question #371
A bag contains 5 red, 4 blue, 3 green balls. Two balls are drawn without replacement. Probability that both are same color is:
A. 15/66
B. 19/66
C. 20/66
D. 12/66
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option B

Explanation:
Total ways C(12,2)=66. Favorable: C(5,2)+C(4,2)+C(3,2) = 10+6+3=19. Probability=19/66.
This question belongs to: Accountancy and Statistics Statistics
Question #372
If P(A)=0.4, P(A∪B)=0.7, then the probability of B will be maximum when A and B are:
A. Mutually exclusive
B. Independent
C. B is a subset of A
D. A is a subset of B
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
P(A∪B)=P(A)+P(B)-P(A∩B). To maximize P(B) given P(A∪B)=0.7 and P(A)=0.4, set P(A∩B)=P(A)=0.4 (i.e., A⊂B). Then 0.7=0.4+P(B)-0.4 => P(B)=0.7 max.
This question belongs to: Accountancy and Statistics Statistics
Question #373
For independent events A and B with P(A)=0.3, P(B)=0.4, the probability that at least one of them occurs is:
A. 0.12
B. 0.70
C. 0.58
D. 0.82
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option C

Explanation:
P(A∪B)=0.3+0.4-0.3×0.4=0.7-0.12=0.58.
This question belongs to: Accountancy and Statistics Statistics
Question #374
Given P(A)=0.5, P(B)=0.3, P(A∩B)=0.1. Are A and B independent?
A. Yes, because they are mutually exclusive
B. Yes, because P(A∩B)=P(A)P(B)
C. Cannot determine
D. No, because 0.1 ≠ 0.15
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option D

Explanation:
P(A)P(B)=0.5×0.3=0.15 ≠ 0.1, so not independent.
This question belongs to: Accountancy and Statistics Statistics
Question #375
A fair coin is tossed until a head appears. The probability that it takes exactly 3 tosses is:
A. 1/4
B. 3/8
C. 1/8
D. 1/2
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option C

Explanation:
Sequence: T, T, H. Probability = (1/2)² * (1/2) = 1/8.
This question belongs to: Accountancy and Statistics Statistics
Question #376
A box contains 3 defective and 7 non-defective items. Two items are selected at random. The probability that exactly one is defective is:
A. 1/5
B. 7/15
C. 21/45
D. 14/45
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option B

Explanation:
Total C(10,2)=45. Favorable: 3×7=21. Probability=21/45=7/15.
This question belongs to: Accountancy and Statistics Statistics
Question #377
If P(A|B) = 0.4 and P(B) = 0.5, P(A∩B) is:
A. 0.8
B. 0.4
C. 0.2
D. 0.9
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option C

Explanation:
P(A∩B) = P(A|B) P(B) = 0.4 × 0.5 = 0.2.
This question belongs to: Accountancy and Statistics Statistics
Question #378
In Bayes' theorem, the probability P(E_i|A) is called:
A. Posterior probability
B. Likelihood
C. Prior probability
D. Marginal probability
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option A

Explanation:
The updated probability after observing the evidence is the posterior probability.
This question belongs to: Accountancy and Statistics Statistics
Question #379
There are two urns: Urn 1 contains 4 white, 6 black; Urn 2 contains 5 white, 5 black. An urn is chosen at random and a ball drawn. If it is white, probability it came from Urn 1 is:
A. 4/9
B. 2/5
C. 1/2
D. 5/9
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option A

Explanation:
P(Urn1|W) = (1/2 * 4/10) / (1/2*4/10 + 1/2*5/10) = 0.2 / (0.2+0.25)=0.2/0.45=4/9.
This question belongs to: Accountancy and Statistics Statistics
Question #380
In the theory of attributes, the total number of objects N is equal to:
A. (AB)+(Aβ)+(αB)+(αβ)
B. Both A and B
C. (A)+(α)
D. (A)+(B)-(AB)
Discuss
Get Complete Subject PDF for Accountancy and Statistics

Correct Answer: Option B

Explanation:
Both identities hold; (A)+(α)=N, and the sum of ultimate class frequencies also equals N.
This question belongs to: Accountancy and Statistics Statistics

More Accountancy and Statistics Topics

Accountancy and Book Keeping MCQs
Today's Top Topics
Accountancy and Book Keeping 1861 Statistics 1318
Explore Subjects
Computer 5279 Maths 5575 Accountancy and Statistics 3179 Science 4298 Static General Knowledge 6362
Practice Mix
Which of the following describes a precompiled collection of SQL statements stored on the database server that can be executed repeatedly by name?
Which major corporate computing entity was founded directly from the evolution of Herman Hollerith’s Tabulating Machine Company?
Total Fertility Rate (TFR) of 2.5 indicates that, on average, women are having:
Choose the antonym of 'YEARNING'.
The median of the dataset: 10, 15, 20, 25, 30, 35 is: