An object weights 10 N in air, 8 N in water. The buoyant force is
A. 10 N
B. 18 N
C. 8 N
D. 2 N
Answer: Option D
Solution (By JKExamLibrary)
Loss in weight = buoyant force = 10 - 8 = 2 N. Weight of displaced water = 2 N. Volume of object = mass of displaced water / density. Archimedes principle.
Explanation:
g decreases with depth: g' = g(1 - d/R). At centre d=R, g'=0. Weightless at centre. At poles g=9.83, equator 9.78. At surface it's maximum.
Explanation:
Beats (periodic amplitude variation from interference of close frequencies) are used to tune instruments: adjust until beats disappear (frequencies match). Also, in Kundt's tube or other methods, beat frequency helps measure sound speed by comparing known and unknown frequencies. Memory tip: 'Beats: tuning (zero beat = matched frequency); speed measurement (beat frequency = |f₁-f₂|)'. This application question tests wave phenomena uses, frequently appearing in competitive exams. Always link physical phenomena to practical applications; competitive exams emphasize real-world relevance of physics concepts.
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