Batsman scored 120 runs with 10 fours, 5 sixes. % runs from running: MCQ with Answer and Explanation
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Question #1
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The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago?
Correct Answer: Option C
Explanation:
P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.
P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.
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Maths
Percentage
Question #2
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A number is increased by 20% and then decreased by 25%. The resulting number is 18 less than the original number. Find the original number.
Correct Answer: Option C
Explanation:
Let original = x. Net multiplier = 1.2 × 0.75 = 0.9. Result = 0.9x = x - 18 → 0.1x = 18 → x = 180. Wait, 0.9x = x - 18 → 0.1x = 18 → x = 180. But option 180 is A. Check: 180 × 1.2 = 216, 216 × 0.75 = 162, 180 - 162 = 18. So x=180. Set correct_answer A. But options: A 180, B 200, C 150, D 120. I'll set A. However, 200 would give 200×1.2=240, ×0.75=180, difference 20. So 180 is correct. I'll adjust options to have 180 as correct. No problem.
Let original = x. Net multiplier = 1.2 × 0.75 = 0.9. Result = 0.9x = x - 18 → 0.1x = 18 → x = 180. Wait, 0.9x = x - 18 → 0.1x = 18 → x = 180. But option 180 is A. Check: 180 × 1.2 = 216, 216 × 0.75 = 162, 180 - 162 = 18. So x=180. Set correct_answer A. But options: A 180, B 200, C 150, D 120. I'll set A. However, 200 would give 200×1.2=240, ×0.75=180, difference 20. So 180 is correct. I'll adjust options to have 180 as correct. No problem.
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Maths
Percentage
Question #3
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Income Rs. 20000, spends 60%. Income rises 25%, savings to increase 50%. % increase in expenditure:
Correct Answer: Option D
Explanation:
Initial: inc 20000, exp 12000, sav 8000. New inc 25000, sav 12000, exp 13000. Increase 1000 on 12000 = 8.33%.
Initial: inc 20000, exp 12000, sav 8000. New inc 25000, sav 12000, exp 13000. Increase 1000 on 12000 = 8.33%.
This question belongs to:
Maths
Percentage
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