If the momentum of a body is increased by 100%, its kinetic energy increases by

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Kinetic energy K = p²/(2m). If p becomes 2p (100% increase), K' = (2p)²/(2m) = 4p²/(2m) = 4K. So increase = 4K - K = 3K, i.e., 300% increase. Common mistake: think linear. Remember quadratic relationship. Percent increase = (new-old)/old × 100% = (4K-K)/K ×100 = 300%.

If the momentum of a body is increased by 100%, its kinetic energy increases by MCQ with Answer and Explanation

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