If the percentage error in measurement of radius of a sphere is 2%, the percentage error in volume is MCQ with Answer and Explanation

If the percentage error in measurement of radius of a sphere is 2%, the percentage error in volume is
A. 4%
B. 8%
C. 6%
D. 2%
Answer: Option C
Solution (By JKExamLibrary)
Volume V = (4/3)πr³, so ΔV/V = 3 Δr/r. Percentage error in volume = 3 × 2% = 6%.

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This question belongs to: Science Physics