If the percentage error in measuring the radius of a sphere is 2%, what will be the percentage error in the calculation of its volume? MCQ with Answer and Explanation

If the percentage error in measuring the radius of a sphere is 2%, what will be the percentage error in the calculation of its volume?
A. 8%
B. 6%
C. 2%
D. 4%
Answer: Option B
Solution (By JKExamLibrary)
The volume of a sphere is given by V = (4/3)πr³. The formula for relative error in volume is (ΔV/V) = 3 × (Δr/r). Since the percentage error in radius (Δr/r × 100) is 2%, the percentage error in volume will be 3 × 2% = 6%. Constants like 4/3 and π do not contribute to the error.

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