In a certain test, 5% of patients have a disease. The test is positive for 90% of diseased and 10% of healthy. If a patient tests positive, the probability they have the disease is about: MCQ with Answer and Explanation

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In a certain test, 5% of patients have a disease. The test is positive for 90% of diseased and 10% of healthy. If a patient tests positive, the probability they have the disease is about:

A. 0.10

B. 0.32

C. 0.50

D. 0.90

Answer: Option B

Solution (By JKExamLibrary)

P(D)=0.05, P(+|D)=0.9, P(+|D')=0.1. P(D|+) = (0.05×0.9) / (0.05×0.9 + 0.95×0.1) = 0.045/(0.045+0.095)=0.045/0.14≈0.321.

This question belongs to: Accountancy and Statistics Statistics

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Practice More Statistics Questions

Question #1 Report Error

Harmonic mean is most appropriate for averaging:

A. Data with extreme outliers

B. Rates and ratios, such as speed or price-earnings ratios

C. Ordinal scale measurements

D. Qualitative data

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Correct Answer: Option B

Explanation:
Harmonic mean is suitable for averaging rates or ratios because it gives equal weight to each data point's reciprocal, preventing distortion from high values in rate calculations.

This question belongs to: Accountancy and Statistics Statistics