Pendulum on planet with g' = 4g. Period becomes:

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T ∝ 1/√g. If g' = 4g, T' = T/√4 = T/2. Higher gravity ⇒ faster oscillations. Memory aid: 'Pendulum: T ∝ 1/√g; 4× gravity ⇒ half period'. Oscillations proportionality frequently tested in competitive exams.

Pendulum on planet with g' = 4g. Period becomes: MCQ with Answer and Explanation

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