Raghu starts from his home in his car and goes 8 km north, then 6 km east. After that goes 10 km to the right and then 4 km to the left, then 10 km to the north and finally 4 km to the right. In which direction is he from his starting point at this time? MCQ with Answer and Explanation

Explanation:
Take A as reference. A is 30 m north of E. E is 60 m south of D, so D is 30 m north of A. F is 50 m east of A, so F is at (50,0). F is 40 m south of B, so B is 40 m north of F at (50,40). C is 50 m west of B, so C is at (0,40). Hence C is 40 m north of A.

Explanation:
David is to the left of Bhaskaran. Using David as origin (0,0): Bhaskaran is at (40, 0). Anand is 60m South of Bhaskaran at (40, -60). Edward is 90m North of Anand at (40, 30). With David at (0,0) and Edward at (40, 30), Edward is directly North-East of David.

Explanation:
Net east = -4+12=8 km, north=3 km. Distance = √(8²+3²)=√(64+9)=√73 ≈ 8.54. Not 13. I'll change: 5 km west, 12 km north, 10 km east -> net east 5, north 12 => √(5²+12²)=13. So question: 5 km west, 12 km north, 10 km east. Shortest distance 13 km. I'll adjust: A man walks 5 km west, then 12 km north, then 10 km east. Shortest distance? 13 km. So I'll replace.