Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is?

A. 51 years

B. 44 years

C. 56 years

D. 102 years

Answer: Option A

Let ages 3k and 8k. Then (3k + 10)/(8k + 10) = 4/10. Solving gives k ≈ 17, age of A = 3*17 = 51.

This question belongs to: Maths Ratio and Proportion

No comments yet. Be the first to start the discussion!

Question #1 Report Error

Two numbers are in the ratio 11:9 and their sum is 682. Find the numbers.

A. 748 and 612

B. 374 and 306

C. 399 and 285

D. 367 and 312

Correct Answer: Option B

Explanation:
Numbers = 11k and 9k. 11k + 9k = 682 ⇒ k = 34. Thus, numbers are 374 and 306.

This question belongs to: Maths Ratio and Proportion

Question #2 Report Error

If a:b = 2:8 and b:c = 8:5, then a:b:c = ?

A. 4:16:10

B. 2:9:5

C. 2:8:5

D. 1:8:6

Correct Answer: Option C

Explanation:
Combine ratios: a:b = 2:8, b:c = 8:5 ⇒ a:b:c = 2:8:5.

This question belongs to: Maths Ratio and Proportion

Question #3 Report Error

If a:b = 2:7 and b:c = 7:12, then a:b:c = ?

A. 4:14:24

B. 2:7:12

C. 1:7:13

D. 2:8:12

Correct Answer: Option B

Explanation:
Combine ratios: a:b = 2:7, b:c = 7:12 ⇒ a:b:c = 2:7:12.

This question belongs to: Maths Ratio and Proportion