Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 10:10. Present age of A is? MCQ with Answer and Explanation
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Question #1
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If a:b = 4:10 and b:c = 10:10, then a:b:c = ?
Correct Answer: Option D
Explanation:
Combine ratios: a:b = 4:10, b:c = 10:10 ⇒ a:b:c = 4:10:10.
Combine ratios: a:b = 4:10, b:c = 10:10 ⇒ a:b:c = 4:10:10.
This question belongs to:
Maths
Ratio and Proportion
Question #2
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Ratio of present ages of A and B is 5:4. After 12 years, the ratio becomes 8:5. Present age of A is?
Correct Answer: Option B
Explanation:
Let ages 5k and 4k. Then (5k + 12)/(4k + 12) = 8/5. Solving gives k ≈ 23, age of A = 5*23 = 115.
Let ages 5k and 4k. Then (5k + 12)/(4k + 12) = 8/5. Solving gives k ≈ 23, age of A = 5*23 = 115.
This question belongs to:
Maths
Ratio and Proportion
Question #3
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Two numbers are in ratio 6:4. Their difference is 60. What is their sum?
Correct Answer: Option D
Explanation:
Numbers 6k, 4k. Difference |6-4|k = 60 ⇒ k = 30. Sum = (6+4)k ≈ 350.
Numbers 6k, 4k. Difference |6-4|k = 60 ⇒ k = 30. Sum = (6+4)k ≈ 350.
This question belongs to:
Maths
Ratio and Proportion
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