Side of square increased 10%. % increase in area: MCQ with Answer and Explanation

Side of square increased 10%. % increase in area:
A. 22%
B. 25%
C. 20%
D. 21%
Answer: Option D
Solution (By JKExamLibrary)
Area multiplier = 1.1² = 1.21, increase 21%.

This question belongs to: Maths Percentage

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Practice More Percentage Questions

Question #1 Report Error
Price reduced 20%, enables buying 5 kg more for Rs. 120. Reduced price/kg:
A. Rs. 4.8
B. Rs. 4
C. Rs. 5
D. Rs. 3.2

Correct Answer: Option D


Explanation:
Original x, xy=120. New 0.8x(y+5)=120 → 0.8×120 + 4x =120 → 96+4x=120 → 4x=24 → x=6, reduced 4.8? Wait: original x=6, reduced price = 0.8*6=4.8, option C. Check: original 6 per kg, 20 kg for 120. Reduced 4.8, buys 25 kg for 120, 5 kg more. So reduced price = 4.8. Option C. So answer C.

This question belongs to: Maths Percentage
Question #2 Report Error
In an election, 20% voters did not vote. Winner got 48% of total votes and won by 2000 votes. Total voters:
A. 10000
B. 12500
C. 15000
D. 12000

Correct Answer: Option B


Explanation:
Let total T. Votes cast = 0.8T. Winner got 0.48T, loser 0.8T - 0.48T = 0.32T. Margin = 0.48T - 0.32T = 0.16T = 2000 → T = 12500.

This question belongs to: Maths Percentage
Question #3 Report Error
A number is increased by 15% and then decreased by 15%. If the resulting number is 782, what was the original number?
A. 780
B. 820
C. 750
D. 800

Correct Answer: Option D


Explanation:
1.15 × 0.85 = 0.9775. 0.9775x = 782 → x = 782/0.9775 = 800.

This question belongs to: Maths Percentage