The amount of heat required to change the state of 1 kg of a substance from solid to liquid at its melting point without any change in temperature is called: MCQ with Answer and Explanation

The amount of heat required to change the state of 1 kg of a substance from solid to liquid at its melting point without any change in temperature is called:
A. Latent heat of fusion
B. Thermal capacity
C. Specific heat capacity
D. Latent heat of vaporization
Answer: Option A
Solution (By JKExamLibrary)
The heat required to change a solid into a liquid at its melting point without a temperature rise is called the Latent Heat of Fusion. The word 'latent' means hidden, because this heat energy breaks intermolecular bonds to change the phase rather than increasing the kinetic energy (temperature) of the molecules.

This question belongs to: Science Physics

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Practice More Physics Questions

Question #1 Report Error
The resolving power of an astronomical telescope can be significantly increased by:
A. Increasing the focal length of the objective lens.
B. Increasing the aperture (diameter) of the objective lens.
C. Decreasing the focal length of the eyepiece.
D. Using light of a longer wavelength.

Correct Answer: Option B


Explanation:
Resolving power is a telescope's ability to distinguish closely spaced objects (like double stars) as separate. It is proportional to D / lambda, where D is the diameter (aperture) of the objective lens and lambda is the wavelength of light. Increasing the aperture D directly and strictly increases the resolving power.

This question belongs to: Science Physics
Question #2 Report Error
The part of human eye that controls amount of light entering is
A. Lens
B. Iris
C. Retina
D. Cornea

Correct Answer: Option B


Explanation:
Iris adjusts pupil size. In bright light pupil constricts, dim light dilates. Retina forms image. Cornea and lens focus. Eye is like camera.

This question belongs to: Science Physics
Question #3 Report Error
Two 60 W bulbs are connected in series across 220 V. Each bulb power becomes (approximately)
A. 60 W
B. 120 W
C. 30 W
D. 15 W

Correct Answer: Option D


Explanation:
Each bulb R = 220²/60 ≈ 807 Ω. Series total R=1614 Ω, current = 220/1614 ≈0.136 A. Power per bulb = I²R = (0.136)²×807 ≈ 15 W.

This question belongs to: Science Physics