The angle of incidence is equal to angle of reflection is the law of MCQ with Answer and Explanation

The angle of incidence is equal to angle of reflection is the law of
A. Dispersion
B. Diffraction
C. Reflection
D. Refraction
Answer: Option C
Solution (By JKExamLibrary)
Law of reflection.

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Practice More Physics Questions

Question #1
The number of significant figures in 0.0034060 is
A. 5
B. 7
C. 6
D. 4

Correct Answer: Option A


Explanation:
Leading zeros (before first non-zero digit) are not significant. So 0.0034060: the first non-zero is 3, then 4,0,6 are significant, and the trailing zero after decimal is significant. Thus significant digits are 3,4,0,6,0 — 5 digits. Note: The last zero indicates precision. Answer is 5.

This question belongs to: Science Physics
Question #2
The energy emitted by the Sun is primarily a result of:
A. Chemical combustion of gases.
B. Nuclear fission of heavy elements.
C. Radioactive decay of uranium.
D. Nuclear fusion of hydrogen into helium.

Correct Answer: Option D


Explanation:
The Sun and other stars generate their immense energy through nuclear fusion. In the Sun's core, immense gravitational pressure and heat cause hydrogen nuclei (protons) to overcome electrostatic repulsion and fuse together to form helium nuclei. This fusion process releases vast amounts of energy according to Einstein's E=mc².

This question belongs to: Science Physics
Question #3
A stone is dropped from a tower. The distance covered by it in the last second of its fall is equal to the distance covered in the first three seconds. The height of the tower is approximately: (g = 10 m/s²)
A. 200 m
B. 125 m
C. 180 m
D. 80 m

Correct Answer: Option B


Explanation:
Distance in first 3 seconds: s₃ = ½gt² = ½×10×9 = 45 m. Let total time be n seconds. Distance in nth second: sₙ = u + g(2n-1)/2 = 0 + 5(2n-1) = 10n - 5. Given sₙ = 45 m ⇒ 10n - 5 = 45 ⇒ n = 5 s. Total height h = ½gn² = ½×10×25 = 125 m. This problem combines equation of motion with logical reasoning about time intervals. Exam tip: For free fall from rest, distance in nth second = 5(2n-1) meters when g=10 m/s². Such numerical problems test application skills in competitive exams.

This question belongs to: Science Physics