The atomic radius of chlorine is smaller than that of sulfur because:
A. Sulfur has a complete octet
B. Chlorine has greater nuclear charge pulling electrons closer
C. Chlorine has fewer electrons
D. Chlorine has more shells
Answer: Option B
Solution (By JKExamLibrary)
Across period 3, S (Z=16) to Cl (Z=17) nuclear charge increases, attracting electron cloud more strongly, reducing atomic radius. Number of shells is same (3).
Explanation:
Down Group 1 (Li → Fr), atomic radius increases due to addition of electron shells. Ionization energy and electronegativity decrease. Reactivity with water increases because the outer electron is more easily lost. Density generally increases, melting/boiling points decrease. Cesium and francium are most reactive. The increase in radius is due to principal quantum number increase.
Explanation:
In the titration of a weak acid with a strong base, the equivalence point occurs in the basic region (pH > 7) due to the hydrolysis of the conjugate base formed. Phenolphthalein changes color in the pH range of 8.2 to 10.0, making it the most suitable indicator for detecting this basic equivalence point.
Explanation:
CH₄ + 2O₂ → CO₂ + 2H₂O + heat. Complete combustion of any hydrocarbon with sufficient oxygen always produces carbon dioxide and water. Incomplete combustion due to limited oxygen produces carbon monoxide (CO) and/or soot (carbon particles). Methane is the main component of natural gas and biogas. CO is a poisonous gas. The combustion of alkanes is highly exothermic.
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