The efficiency of an ideal Carnot engine operating between two temperatures T1 (source) and T2 (sink) is given by:
A. T2 / (T1 - T2)
B. 1 - (T1/T2)
C. 1 - (T2/T1)
D. (T1 - T2) / T2
Answer: Option C
Solution (By JKExamLibrary)
The thermal efficiency (η) of a reversible Carnot engine depends exclusively on the absolute temperatures of the hot source (T1) and the cold sink (T2). The formula is η = 1 - (T2/T1), or (T1 - T2) / T1. Temperatures must be in Kelvin. It shows no engine can be 100% efficient unless the sink is at absolute zero.
Explanation:
Higher frequency → higher pitch. Amplitude increases loudness. Wavelength inversely proportional to frequency (v constant). So increasing frequency increases pitch.
Explanation:
Fuse needs low melting point to melt at overload, high resistance to generate more heat (I²R). Tin-lead alloy suitable. Copper high melting point, not fuse material.
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