The freezing point of mercury is -39°C. It cannot be used in thermometers for temperatures below this because MCQ with Answer and Explanation

The freezing point of mercury is -39°C. It cannot be used in thermometers for temperatures below this because
A. It expands
B. It freezes
C. It becomes transparent
D. It evaporates
Answer: Option B
Solution (By JKExamLibrary)
Below freezing point, mercury solidifies and doesn't work. Alcohol thermometers used for low temps.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
Two resistance wires of same material and same length have diameters in ratio 2:1. Their resistances are in ratio
A. 2:1
B. 1:2
C. 4:1
D. 1:4

Correct Answer: Option D


Explanation:
R ∝ L/A ∝ 1/d². So R₁/R₂ = (d₂/d₁)² = (1/2)² = 1/4 = 1:4.

This question belongs to: Science Physics
Question #2
If the error in measurement of radius of a sphere is 2%, the percentage error in the calculated volume of the sphere will be:
A. 8%
B. 2%
C. 6%
D. 4%

Correct Answer: Option C


Explanation:
Volume of sphere V = (4/3)πr³. For error propagation, percentage error in V = 3 × (percentage error in r). Given error in r is 2%, so error in V = 3 × 2% = 6%. This follows the power rule: if Q = xⁿ, then % error in Q = |n| × % error in x. This principle is crucial for experimental error analysis. Exam tip: Remember that volume depends on cube of radius, so errors amplify threefold. This type of question tests understanding of error propagation in derived quantities.

This question belongs to: Science Physics
Question #3
A car moving with speed 54 km/h is stopped in 5 s. The distance covered before stop is
A. 54 m
B. 75 m
C. 37.5 m
D. 27 m

Correct Answer: Option C


Explanation:
54 km/h = 15 m/s. u=15, v=0, t=5. a = (0-15)/5 = -3 m/s². s = ut+½at² = 15×5 + ½×(-3)×25 = 75 - 37.5 = 37.5 m. Or s = (u+v)/2 × t = 7.5×5 = 37.5 m.

This question belongs to: Science Physics