The latent heat of fusion of ice is 80 cal/g. Heat required to melt 50 g ice at 0°C is

Question

Team JKExamLibrary · Accepted Answer

Q = mL = 50 × 80 = 4000 cal. (1 cal = 4.2 J, but here in cal). No temperature change during phase change. Latent heat of vaporization is 540 cal/g for water.

The latent heat of fusion of ice is 80 cal/g. Heat required to melt 50 g ice at 0°C is MCQ with Answer and Explanation

Solution (By JKExamLibrary)

Discuss this Question (0)

Practice More Physics Questions