The least count of a standard vernier calliper is generally MCQ with Answer and Explanation

The least count of a standard vernier calliper is generally
A. 0.01 cm
B. 1 cm
C. 0.001 cm
D. 0.1 cm
Answer: Option A
Solution (By JKExamLibrary)
Least count = 1 MSD - 1 VSD = 0.1 - 0.09 = 0.01 cm (common).

This question belongs to: Science Physics

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Question #1 Report Error
Electromagnetic induction was discovered by
A. Ampere
B. Coulomb
C. Oersted
D. Faraday

Correct Answer: Option D


Explanation:
Michael Faraday discovered electromagnetic induction in 1831: changing magnetic field induces emf. Oersted discovered magnetic effect of current. Ampere gave laws of magnetic force between currents. Coulomb for electrostatics.

This question belongs to: Science Physics
Question #2 Report Error
Alpha particles are
A. Electrons
B. Protons
C. Helium nuclei
D. Electromagnetic waves

Correct Answer: Option C


Explanation:
Alpha particles are helium nuclei (2 protons, 2 neutrons), charge +2e, mass 4 u. Beta particles are fast electrons (or positrons). Gamma rays are high-energy photons, no mass, no charge.

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Question #3 Report Error
The time period of a simple pendulum is measured as 2.0 s with an error of 0.1 s. The percentage error in the calculated value of g is approximately:
A. 2.5%
B. 5%
C. 10%
D. 20%

Correct Answer: Option C


Explanation:
Pendulum period T = 2π√(l/g) ⇒ g = 4π²l/T². For error propagation, % error in g = % error in l + 2 × % error in T. Assuming l measured precisely, % error in g ≈ 2 × (% error in T). % error in T = (0.1/2.0)×100% = 5%. Thus % error in g ≈ 2×5% = 10%. Memory tip: 'g ∝ 1/T² ⇒ %Δg = 2 × %ΔT'. This error analysis problem tests experimental physics skills, frequently appearing in competitive exams. Always apply power rule for error propagation: if Q ∝ xⁿ, %ΔQ = |n| × %Δx.

This question belongs to: Science Physics