The magnetic field inside a long, straight, current-carrying solenoid is:
A. Directly proportional to the radius of the solenoid
B. Uniform (same at all points)
C. Zero
D. Stronger at the ends than at the center
Answer: Option B
Solution (By JKExamLibrary)
An ideal solenoid consists of tightly packed coils. When current passes through it, the magnetic field lines inside the solenoid are parallel straight lines. This indicates that the magnetic field is uniform in magnitude and direction at all points strictly inside the central region of the solenoid. The field strength is given by B = mu_0 * n * I.
Explanation:
v = c/n = 3×10⁸/1.5 = 2×10⁸ m/s. Direct refractive index formula application. Memory tip: 'Higher n ⇒ slower light; v = c/n'. Basic optics calculation frequently tested in competitive exams to verify formula recall and unit handling.
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