The oxidation state of Cr in potassium dichromate (K2Cr2O7) is: MCQ with Answer and Explanation

The oxidation state of Cr in potassium dichromate (K2Cr2O7) is:
A. +2
B. +7
C. +6
D. +3
Answer: Option C
Solution (By JKExamLibrary)
In K2Cr2O7, potassium has an oxidation state of +1 and oxygen is -2. Let the oxidation state of Cr be x. The sum of oxidation states in a neutral molecule is zero: 2(+1) + 2(x) + 7(-2) = 0. Solving this gives 2 + 2x - 14 = 0, so 2x = 12, and x = +6.

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Correct Answer: Option D


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