The population of a town increases by 15% in the first year and decreases by 10% in the second year. If the population at the end of second year is 10350, what was the population at the beginning? MCQ with Answer and Explanation
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Question #1
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A's salary 15% less than B's. By what % must A's salary be raised to equal B's?
Correct Answer: Option A
Explanation:
A=85, B=100. Increase needed = (15/85)×100 ≈ 17.65%.
A=85, B=100. Increase needed = (15/85)×100 ≈ 17.65%.
This question belongs to:
Maths
Percentage
Question #2
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The population of a town is 10,000. It increases by 10% annually. What will be the population after 2 years?
Correct Answer: Option D
Explanation:
Population = P * (1 + R/100)^t = 10000 * (1.10)^2 = 10000 * 1.21 = 12100.
Population = P * (1 + R/100)^t = 10000 * (1.10)^2 = 10000 * 1.21 = 12100.
This question belongs to:
Maths
Percentage
Question #3
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Price of rice reduced by 20%, allowing a person to buy 5 kg more for Rs. 120. Reduced price per kg is:
Correct Answer: Option A
Explanation:
Original x, xy=120. New 0.8x(y+5)=120 → 96+4x=120 → x=6, reduced price = 4.8.
Original x, xy=120. New 0.8x(y+5)=120 → 96+4x=120 → x=6, reduced price = 4.8.
This question belongs to:
Maths
Percentage
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