The process by which heat from the Sun reaches Earth is MCQ with Answer and Explanation
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Question #1
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If the error in the measurement of the momentum of a particle is +100%, what will be the percentage error in the measurement of its kinetic energy?
Correct Answer: Option C
Explanation:
Kinetic Energy (K) is given by K = p^2 / 2m. If momentum (p) increases by 100%, the new momentum is p' = p + 1.0p = 2p. The new kinetic energy is K' = (2p)^2 / 2m = 4(p^2 / 2m) = 4K. The increase is 4K - K = 3K. Percentage increase = (3K/K) * 100 = 300%.
Kinetic Energy (K) is given by K = p^2 / 2m. If momentum (p) increases by 100%, the new momentum is p' = p + 1.0p = 2p. The new kinetic energy is K' = (2p)^2 / 2m = 4(p^2 / 2m) = 4K. The increase is 4K - K = 3K. Percentage increase = (3K/K) * 100 = 300%.
Question #2
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Nuclear fission involves:
Correct Answer: Option A
Explanation:
Nuclear fission is the splitting of a heavy nucleus (e.g., uranium-235, plutonium-239) into lighter nuclei, releasing energy and neutrons. This process powers nuclear reactors and atomic bombs. Fusion combines light nuclei (e.g., hydrogen to helium), powering stars. Memory aid: 'Fission = splitting heavy; Fusion = joining light'. This conceptual question tests understanding of nuclear reactions, frequently examined in competitive exams. Always link fission to chain reactions (neutrons induce further fissions) and critical mass concepts.
Nuclear fission is the splitting of a heavy nucleus (e.g., uranium-235, plutonium-239) into lighter nuclei, releasing energy and neutrons. This process powers nuclear reactors and atomic bombs. Fusion combines light nuclei (e.g., hydrogen to helium), powering stars. Memory aid: 'Fission = splitting heavy; Fusion = joining light'. This conceptual question tests understanding of nuclear reactions, frequently examined in competitive exams. Always link fission to chain reactions (neutrons induce further fissions) and critical mass concepts.
Question #3
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The primary principle behind the working of a potentiometer is that the potential drop across any length of a uniform wire carrying a constant steady current is:
Correct Answer: Option A
Explanation:
A potentiometer uses a long wire of uniform cross-section and composition. When a constant steady current flows through it, Ohm's law (V = IR) and the resistance formula (R = rhoL/A) combine to give V = I(rho/A)L. Since I, rho, and A are constant, the potential drop V is strictly directly proportional to the length L of the wire.
A potentiometer uses a long wire of uniform cross-section and composition. When a constant steady current flows through it, Ohm's law (V = IR) and the resistance formula (R = rhoL/A) combine to give V = I(rho/A)L. Since I, rho, and A are constant, the potential drop V is strictly directly proportional to the length L of the wire.
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