The radius of the nth Bohr orbit in hydrogen atom is proportional to:
A. 1/n²
B. n²
C. n
D. 1/n
Answer: Option B
Solution (By JKExamLibrary)
Bohr model: radius r_n = (4πε₀ħ²n²)/(m_e e²) = n² a₀, where a₀ is Bohr radius (≈0.529 Å). Thus r_n ∝ n². Energy E_n ∝ -1/n². Memory tip: 'Bohr radius: r ∝ n²; energy: E ∝ -1/n²'. This atomic physics formula is frequently tested in competitive exams. Always recall that n is principal quantum number; higher n means larger orbit, less tightly bound electron. This problem assesses understanding of quantization in early quantum theory.
Explanation:
Atomic diameter ~ 1 Å = 10⁻¹⁰ m. Nucleus is 10⁻¹⁵ m (femtometre). Atomic size determined by electron cloud. 10⁻⁶ m is typical cell size. 10⁻³ m is millimetre.
No comments yet. Be the first to start the discussion!