The time period of a geostationary satellite is: MCQ with Answer and Explanation

The time period of a geostationary satellite is:
A. 24 hours
B. 365 days
C. 12 hours
D. 27.3 days
Answer: Option A
Solution (By JKExamLibrary)
A geostationary satellite orbits the Earth directly over the equator at an altitude of ~35,786 km. It revolves in the same direction the Earth rotates. Its orbital period perfectly matches Earth's rotational period, which is 24 hours. Because of this, it appears entirely stationary from any point on Earth's surface, making it ideal for communications and DTH TV.

This question belongs to: Science Physics

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Question #1 Report Error
Assertion (A): The velocity of sound is greater in solids than in gases. Reason (R): Solids possess higher elasticity compared to gases.
A. A is true but R is false.
B. Both A and R are true and R is the correct explanation of A.
C. A is false but R is true.
D. Both A and R are true but R is NOT the correct explanation of A.

Correct Answer: Option B


Explanation:
The velocity of sound in a medium is determined by the formula v = √(E/ρ), where E is the modulus of elasticity and ρ is the density. Although solids are denser, their modulus of elasticity (bulk modulus) is tremendously higher than that of gases, overwhelmingly compensating for the density. Hence, sound travels fastest in solids.

This question belongs to: Science Physics
Question #2 Report Error
A 40 W tube light consumes _____ energy in 8 hours.
A. 5 kWh
B. 0.32 kWh
C. 320 kWh
D. 0.04 kWh

Correct Answer: Option B


Explanation:
Energy = 0.04 kW × 8 h = 0.32 kWh.

This question belongs to: Science Physics
Question #3 Report Error
Which of the following prefix represents 10⁻¹⁵?
A. Femto
B. Pico
C. Atto
D. Nano

Correct Answer: Option A


Explanation:
Femto (f) = 10⁻¹⁵. Pico (p) = 10⁻¹², nano (n) = 10⁻⁹, atto (a) = 10⁻¹⁸. The prefix chain: milli 10⁻³, micro 10⁻⁶, nano 10⁻⁹, pico 10⁻¹², femto 10⁻¹⁵, atto 10⁻¹⁸. Mnemonic: Femto is 'fifteen'.

This question belongs to: Science Physics