The time period of a seconds pendulum is MCQ with Answer and Explanation

The time period of a seconds pendulum is
A. 0.5 s
B. 2 s
C. 4 s
D. 1 s
Answer: Option B
Solution (By JKExamLibrary)
Seconds pendulum has period 2 s (1 s each swing).

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Practice More Physics Questions

Question #1
A car moving at constant velocity of 10 m/s has net force acting on it equal to
A. Weight of car
B. Frictional force
C. Zero
D. Force of engine

Correct Answer: Option C


Explanation:
Constant velocity implies zero acceleration, net force = 0 by Newton's first law. Engine force balances friction and air resistance. Net force zero, not necessarily zero forces.

This question belongs to: Science Physics
Question #2
The relation V = IR is applicable to
A. Ohmic conductors
B. Non-ohmic devices
C. Semiconductors
D. Gaseous conductors

Correct Answer: Option A


Explanation:
Ohm's law V=IR is linear relationship, valid for ohmic materials like metals at constant temperature. Non-ohmic do not follow linear I-V. Semiconductors are non-ohmic.

This question belongs to: Science Physics
Question #3
The magnetic field at the center of a circular coil of radius R carrying current I is:
A. μ₀I/(4R)
B. μ₀NI/(4πR)
C. μ₀NI/(2R)
D. μ₀I/(2R)

Correct Answer: Option C


Explanation:
For a circular coil with N turns, magnetic field at center B = μ₀NI/(2R). For single turn (N=1), B = μ₀I/(2R). This derives from Biot-Savart law. Option A is for single turn; B and D have incorrect constants. Memory tip: 'Coil center: B = μ₀NI/(2R); straight wire: B = μ₀I/(2πr)'. This formula application is frequently tested in magnetism sections of competitive exams. Always note number of turns N; competitive exams often include it to test attention to detail.

This question belongs to: Science Physics