The value of acceleration due to gravity g on the surface of Earth depends on MCQ with Answer and Explanation

The value of acceleration due to gravity g on the surface of Earth depends on
A. Mass of the object
B. Shape of the object
C. Rotation of the object
D. Mass of the Earth
Answer: Option D
Solution (By JKExamLibrary)
g = GM/R², where M is mass of Earth, R radius, G universal constant. It does not depend on mass of falling object (Galileo's experiment). Earth's rotation causes slight variation but surface g is primarily determined by M and R. So mass of Earth is factor.

This question belongs to: Science Physics

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Practice More Physics Questions

Question #1 Report Error
A car accelerates uniformly from rest to a speed of 72 km/h in 10 seconds. What is the distance covered during this time?
A. 200 m
B. 720 m
C. 100 m
D. 400 m

Correct Answer: Option C


Explanation:
First, convert speed to SI units: 72 km/h = 72 × (5/18) m/s = 20 m/s. Initial velocity (u) = 0, final velocity (v) = 20 m/s, time (t) = 10 s. Acceleration (a) = (v-u)/t = 20/10 = 2 m/s². Distance (s) = ut + (1/2)at² = 0 + 0.5 × 2 × 10² = 100 meters.

This question belongs to: Science Physics
Question #2 Report Error
The time period of revolution of a geostationary satellite is:
A. 12 hours
B. 24 hours
C. Variable
D. 84 minutes

Correct Answer: Option B


Explanation:
Geostationary satellites orbit in Earth's equatorial plane with period matching Earth's rotation period (24 hours), so they appear stationary relative to ground. Orbital radius is about 42,000 km from Earth's center. Memory tip: 'Geostationary: T=24 h, equatorial orbit, fixed position; used for communication/weather satellites'. This standard result is frequently tested in competitive exams. Always recall that geostationary is a special case of geosynchronous (same period) with zero inclination; competitive exams often compare low orbit (84 min) vs geostationary (24 h) periods.

This question belongs to: Science Physics
Question #3 Report Error
A piece of ice floats in water with 1/10 of its volume above water. The density of ice is
A. 0.5 g/cm³
B. 1.0 g/cm³
C. 0.8 g/cm³
D. 0.9 g/cm³

Correct Answer: Option D


Explanation:
Fraction of volume submerged = ρ_ice / ρ_water. If 1/10 above, 9/10 submerged. So ρ_ice/ρ_water = 9/10 => ρ_ice = 0.9 g/cm³. Density of ice is 0.9 g/cm³.

This question belongs to: Science Physics