The work done by a conservative force acting on a particle moving around any closed path is: MCQ with Answer and Explanation

The work done by a conservative force acting on a particle moving around any closed path is:
A. Negative
B. Depends on the path taken
C. Positive
D. Zero
Answer: Option D
Solution (By JKExamLibrary)
By definition, a force is conservative if the work done by it on an object moving between two points is completely independent of the path taken. A direct consequence of this is that the total work done by a conservative force (like gravity or electrostatic force) in moving an object around a closed loop (returning to the starting point) is exactly zero.

This question belongs to: Science Physics

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Practice More Physics Questions

Question #1 Report Error
The phenomenon of beats can be observed when two sound waves have:
A. Very different frequencies
B. Same frequency but different amplitudes
C. Slightly different frequencies
D. Same frequency and amplitude

Correct Answer: Option C


Explanation:
Beats occur due to interference of two waves with slightly different frequencies (Δf small, typically < 10 Hz for audible beats). The beat frequency is |f₁ - f₂|, causing periodic loudness variation. Same frequency (A, B) produces steady interference (no beats); very different frequencies (D) produce rapid fluctuations not perceived as beats. Memory aid: 'Beats: |f₁ - f₂| small ⇒ audible pulsations; used in tuning'. This wave phenomenon question tests superposition understanding, frequently examined in competitive exams. Always link beat perception to frequency difference magnitude; competitive exams often test qualitative conditions for observable beats.

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Question #2 Report Error
Momentum is conserved in
A. No collisions
B. Only elastic collisions
C. All collisions
D. Only inelastic collisions

Correct Answer: Option C


Explanation:
Momentum conserved in all collisions if no external force. KE conserved only in elastic.

This question belongs to: Science Physics
Question #3 Report Error
In the equation F = ma, if mass is doubled and acceleration is halved, force becomes
A. Half
B. Double
C. Same
D. Four times

Correct Answer: Option C


Explanation:
F = m×a. New force F' = (2m)×(a/2) = m×a = F. So force remains unchanged. This is direct proportionality. Understand the relationship: doubling mass doubles force, halving acceleration halves it, net effect no change.

This question belongs to: Science Physics