Three resistors of 2Ω, 3Ω, and 6Ω are connected in parallel. The equivalent resistance is: MCQ with Answer and Explanation

Three resistors of 2Ω, 3Ω, and 6Ω are connected in parallel. The equivalent resistance is:
A.
B.
C. 11Ω
D. 0.5Ω
Answer: Option B
Solution (By JKExamLibrary)
For parallel combination: 1/R_eq = 1/R₁ + 1/R₂ + 1/R₃ = 1/2 + 1/3 + 1/6 = (3+2+1)/6 = 6/6 = 1. Thus R_eq = 1Ω. Note: Equivalent resistance in parallel is always less than the smallest individual resistance (here 2Ω). Memory tip: 'Parallel: reciprocal sum; result < min(R)'. This standard calculation tests parallel resistance formula application, frequently appearing in competitive exams. Always simplify fractions carefully; common denominator method avoids errors. Verify: 1Ω < 2Ω, consistent with parallel behavior.

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