Two 100 W, 200 V bulbs are connected in series across 200 V supply. Total power consumed is
A. 100 W
B. 200 W
C. 50 W
D. 25 W
Answer: Option C
Solution (By JKExamLibrary)
Each bulb resistance R = V²/P = 40000/100 = 400 Ω. In series, total R = 800 Ω. Total power P_total = V²/(total R) = 200²/800 = 40000/800 = 50 W. So each bulb gets 25 W. Series reduces power.
Explanation:
Electric generator (dynamo/alternator) works on electromagnetic induction: mechanical rotation induces emf. Motor does opposite. Transformer changes voltage. Battery converts chemical to electrical.
Explanation:
Acceleration a = dv/dt = d(3t² + 2t)/dt = 6t + 2. At t = 2 s: a = 6(2) + 2 = 14 m/s². Differentiation of velocity gives instantaneous acceleration. Memory tip: a = dv/dt; for polynomial v(t), differentiate term by term. Tests calculus application in kinematics, common in advanced competitive exam questions.
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