Two alloys contain 70% and 40% copper respectively. In what ratio must they be mixed to obtain an alloy containing 50% copper? MCQ with Answer and Explanation

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Two alloys contain 70% and 40% copper respectively. In what ratio must they be mixed to obtain an alloy containing 50% copper?

A. 1:2

B. 2:1

C. 3:2

D. 1:1

Answer: Option A

Solution (By JKExamLibrary)

By alligation: (70-50):(50-40) = 20:10 = 2:1. The ratio of the alloys is inverse: 1:2.

This question belongs to: Maths Percentage

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Question #1 Report Error

Due to 20% reduction in price, a man can buy 2 kg more sugar for Rs. 60. Original price per kg:

A. Rs. 6

B. Rs. 7.5

C. Rs. 8

D. Rs. 5

View Answer & Solution Discuss

Correct Answer: Option A

Explanation:
Original x, xy=60. 0.8x(y+2)=60 → 48 + 1.6x =60 → 1.6x=12 → x=7.5? Wait: 0.8x(y+2)=0.8xy + 1.6x =0.8*60 + 1.6x =48+1.6x=60 → 1.6x=12 → x=7.5, not 6. So if x=7.5, original price 7.5, reduced 6. So reduced price 6. So I'll ask reduced price: 6. Or ask original 7.5. Options given: 5,6,7.5,8. So correct answer 7.5. So original price Rs.7.5.

This question belongs to: Maths Percentage