Two numbers are in ratio 10:12. Their difference is 61. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 10:12. Their difference is 61. What is their sum?
A. 198
B. 279
C. 99
D. 238
Answer: Option A
Solution (By JKExamLibrary)
Numbers 10k, 12k. Difference |10-12|k = 61 ⇒ k = 30. Sum = (10+12)k ≈ 198.

This question belongs to: Maths Ratio and Proportion

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Ratio and Proportion Questions

Question #1 Report Error
Two numbers are in ratio 6:8. Their difference is 69. What is their sum?
A. 368
B. 283
C. 224
D. 112

Correct Answer: Option C


Explanation:
Numbers 6k, 8k. Difference |6-8|k = 69 ⇒ k = 34. Sum = (6+8)k ≈ 224.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
If a:b = 3:9 and b:c = 9:10, then a:b:c = ?
A. 3:10:10
B. 3:9:10
C. 6:18:20
D. 2:9:11

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 3:9, b:c = 9:10 ⇒ a:b:c = 3:9:10.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
Ratio of present ages of A and B is 3:7. After 5 years, the ratio becomes 5:10. Present age of A is?
A. 72 years
B. 77 years
C. 65 years
D. 144 years

Correct Answer: Option A


Explanation:
Let ages 3k and 7k. Then (3k + 5)/(7k + 5) = 5/10. Solving gives k ≈ 24, age of A = 3*24 = 72.

This question belongs to: Maths Ratio and Proportion