Two numbers are in ratio 11:6. Their difference is 58. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 11:6. Their difference is 58. What is their sum?
A. 272
B. 391
C. 310
D. 136
Answer: Option A
Solution (By JKExamLibrary)
Numbers 11k, 6k. Difference |11-6|k = 58 ⇒ k = 11. Sum = (11+6)k ≈ 272.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
If a:b = 4:3 and b:c = 3:6, then a:b:c = ?
A. 3:3:7
B. 4:4:6
C. 8:6:12
D. 4:3:6

Correct Answer: Option D


Explanation:
Combine ratios: a:b = 4:3, b:c = 3:6 ⇒ a:b:c = 4:3:6.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
If a:b = 4:6 and b:c = 6:12, then a:b:c = ?
A. 3:6:13
B. 4:7:12
C. 8:12:24
D. 4:6:12

Correct Answer: Option D


Explanation:
Combine ratios: a:b = 4:6, b:c = 6:12 ⇒ a:b:c = 4:6:12.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
Find the mean proportional between 29 and 50.
A. 41
B. 76
C. 79
D. 38

Correct Answer: Option D


Explanation:
Mean proportional = √(29 × 50) = √(1450) = 38.

This question belongs to: Maths Ratio and Proportion