Two numbers are in ratio 11:7. Their difference is 58. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 11:7. Their difference is 58. What is their sum?
A. 126
B. 252
C. 350
D. 280
Answer: Option B
Solution (By JKExamLibrary)
Numbers 11k, 7k. Difference |11-7|k = 58 ⇒ k = 14. Sum = (11+7)k ≈ 252.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
If a:b = 6:7 and b:c = 7:4, then a:b:c = ?
A. 12:14:8
B. 6:7:4
C. 6:8:4
D. 5:7:5

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 6:7, b:c = 7:4 ⇒ a:b:c = 6:7:4.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
Find the mean proportional between 11 and 61.
A. 25
B. 28
C. 72
D. 50

Correct Answer: Option A


Explanation:
Mean proportional = √(11 × 61) = √(671) = 25.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
If a:b = 8:4 and b:c = 4:11, then a:b:c = ?
A. 7:4:12
B. 8:4:11
C. 16:8:22
D. 8:5:11

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 8:4, b:c = 4:11 ⇒ a:b:c = 8:4:11.

This question belongs to: Maths Ratio and Proportion