Two numbers are in ratio 4:12. Their difference is 122. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 4:12. Their difference is 122. What is their sum?
A. 104
B. 244
C. 208
D. 338
Answer: Option C
Solution (By JKExamLibrary)
Numbers 4k, 12k. Difference |4-12|k = 122 ⇒ k = 15. Sum = (4+12)k ≈ 208.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
If a:b = 2:6 and b:c = 6:11, then a:b:c = ?
A. 2:7:11
B. 4:12:22
C. 2:6:11
D. 1:6:12

Correct Answer: Option C


Explanation:
Combine ratios: a:b = 2:6, b:c = 6:11 ⇒ a:b:c = 2:6:11.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
Two numbers are in ratio 12:10. Their difference is 74. What is their sum?
A. 387
B. 132
C. 264
D. 312

Correct Answer: Option C


Explanation:
Numbers 12k, 10k. Difference |12-10|k = 74 ⇒ k = 37. Sum = (12+10)k ≈ 264.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
Find the mean proportional between 32 and 50.
A. 82
B. 43
C. 40
D. 80

Correct Answer: Option C


Explanation:
Mean proportional = √(32 × 50) = √(1600) = 40.

This question belongs to: Maths Ratio and Proportion