Two numbers are in ratio 6:12. Their difference is 108. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 6:12. Their difference is 108. What is their sum?
A. 207
B. 554
C. 447
D. 414
Answer: Option D
Solution (By JKExamLibrary)
Numbers 6k, 12k. Difference |6-12|k = 108 ⇒ k = 18. Sum = (6+12)k ≈ 414.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
Find the mean proportional between 22 and 16.
A. 21
B. 18
C. 38
D. 36

Correct Answer: Option B


Explanation:
Mean proportional = √(22 × 16) = √(352) = 18.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
Ratio of present ages of A and B is 6:5. After 5 years, the ratio becomes 9:6. Present age of A is?
A. 90 years
B. 85 years
C. 180 years
D. 95 years

Correct Answer: Option A


Explanation:
Let ages 6k and 5k. Then (6k + 5)/(5k + 5) = 9/6. Solving gives k ≈ 15, age of A = 6*15 = 90.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
If a:b = 8:5 and b:c = 5:6, then a:b:c = ?
A. 16:10:12
B. 7:5:7
C. 8:6:6
D. 8:5:6

Correct Answer: Option D


Explanation:
Combine ratios: a:b = 8:5, b:c = 5:6 ⇒ a:b:c = 8:5:6.

This question belongs to: Maths Ratio and Proportion