Two numbers are in ratio 8:11. Their difference is 86. What is their sum? MCQ with Answer and Explanation
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Question #1
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Ratio of present ages of A and B is 6:5. After 5 years, the ratio becomes 9:6. Present age of A is?
Correct Answer: Option B
Explanation:
Let ages 6k and 5k. Then (6k + 5)/(5k + 5) = 9/6. Solving gives k ≈ 15, age of A = 6*15 = 90.
Let ages 6k and 5k. Then (6k + 5)/(5k + 5) = 9/6. Solving gives k ≈ 15, age of A = 6*15 = 90.
This question belongs to:
Maths
Ratio and Proportion
Question #2
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If a:b = 3:3 and b:c = 3:7, then a:b:c = ?
Correct Answer: Option A
Explanation:
Combine ratios: a:b = 3:3, b:c = 3:7 ⇒ a:b:c = 3:3:7.
Combine ratios: a:b = 3:3, b:c = 3:7 ⇒ a:b:c = 3:3:7.
This question belongs to:
Maths
Ratio and Proportion
Question #3
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Two numbers are in the ratio 11:5 and their sum is 789. Find the numbers.
Correct Answer: Option B
Explanation:
Numbers = 11k and 5k. 11k + 5k = 789 ⇒ k = 49. Thus, numbers are 539 and 245.
Numbers = 11k and 5k. 11k + 5k = 789 ⇒ k = 49. Thus, numbers are 539 and 245.
This question belongs to:
Maths
Ratio and Proportion
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