When a body is taken to a height equal to radius of Earth from surface, its weight becomes MCQ with Answer and Explanation
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Question #1
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The phenomenon of beats in sound waves is due to:
Correct Answer: Option D
Explanation:
Beats occur when two sound waves of slightly different frequencies interfere, causing periodic variation in amplitude (loudness). Beat frequency = |f₁ - f₂|. This is a superposition/interference phenomenon. Reflection, refraction, diffraction don't produce beats. Memory tip: 'Beats = interference of close frequencies; used in tuning instruments'. This conceptual question tests wave superposition understanding, frequently examined in competitive exams. Always distinguish beats (amplitude modulation) from resonance (amplitude increase at natural frequency).
Beats occur when two sound waves of slightly different frequencies interfere, causing periodic variation in amplitude (loudness). Beat frequency = |f₁ - f₂|. This is a superposition/interference phenomenon. Reflection, refraction, diffraction don't produce beats. Memory tip: 'Beats = interference of close frequencies; used in tuning instruments'. This conceptual question tests wave superposition understanding, frequently examined in competitive exams. Always distinguish beats (amplitude modulation) from resonance (amplitude increase at natural frequency).
Question #2
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The radius of curvature of a convex mirror of focal length 20 cm is
Question #3
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The work done in moving a charge of 2 C between two points with potential difference of 12 V is:
Correct Answer: Option C
Explanation:
Work done W = charge (Q) × potential difference (V). Thus W = 2 C × 12 V = 24 J. This follows from definition of voltage: 1 volt = 1 joule per coulomb. The work done equals the change in electrical potential energy. This fundamental relationship is crucial in electricity. Memory tip: W = QV is analogous to mechanical work = force × distance. Such direct formula applications are common in competitive exams to test basic concept retention. Always verify units: coulomb × volt = joule, confirming dimensional consistency.
Work done W = charge (Q) × potential difference (V). Thus W = 2 C × 12 V = 24 J. This follows from definition of voltage: 1 volt = 1 joule per coulomb. The work done equals the change in electrical potential energy. This fundamental relationship is crucial in electricity. Memory tip: W = QV is analogous to mechanical work = force × distance. Such direct formula applications are common in competitive exams to test basic concept retention. Always verify units: coulomb × volt = joule, confirming dimensional consistency.
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