When a small spherical metal body falls through a highly viscous liquid, it attains a terminal velocity. This terminal velocity is directly proportional to: MCQ with Answer and Explanation

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When a small spherical metal body falls through a highly viscous liquid, it attains a terminal velocity. This terminal velocity is directly proportional to:

A. The square root of the radius of the sphere

B. The radius of the sphere

C. The inverse of the radius of the sphere

D. The square of the radius of the sphere

Answer: Option D

Solution (By JKExamLibrary)

According to Stokes' Law, the terminal velocity (Vt) of a spherical body falling through a viscous medium is given by Vt = 2r^2(rho - sigma)g / 9(eta). Here, r is the radius. The formula clearly shows that the terminal velocity is directly proportional to the square of the radius (r^2).

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