X can do a piece of work in 40 days. He works at it for 8 days and then Y alone finishes the remaining work in 16 days. How long will X and Y together take to complete the work? MCQ with Answer and Explanation

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X can do a piece of work in 40 days. He works at it for 8 days and then Y alone finishes the remaining work in 16 days. How long will X and Y together take to complete the work?

A. 13(1/3) days

B. 16 days

C. 15 days

D. 14 days

Answer: Option A

Solution (By JKExamLibrary)

Let total work be 40 units. Efficiency of X = 1 unit/day. In 8 days, X completes 8 units. Remaining work = 40 - 8 = 32 units. Y finishes 32 units in 16 days, so Y's efficiency = 32 / 16 = 2 units/day. Combined efficiency of X and Y = 1 + 2 = 3 units/day. Time taken together = 40 / 3 = 13(1/3) days.

This question belongs to: Maths Time and Work

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Question #1 Report Error

A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?

A. 1/6

B. 1/9

C. 2/5

D. 1/4

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Correct Answer: Option A

Explanation:
Time taken by A = 18 days, so B takes 9 days. Efficiency of A = 1/18, B = 1/9. Together in one day = 1/18 + 1/9 = 3/18 = 1/6.

This question belongs to: Maths Time and Work