Correct Answer: Option D
Explanation:
Total work = LCM(10, 15, 20) = 60 units. Efficiency of A = 6, B = 4, C = 3. Let the total work last for x days. A worked for 2 days, so work done = 2 * 6 = 12 units. Remaining work = 60 - 12 = 48 units. B worked for (x - 2) days and C worked for x days. Therefore, 4(x - 2) + 3x = 48 => 4x - 8 + 3x = 48 => 7x = 56 => x = 8 days.
This question belongs to:
Maths
Time and Work
No comments yet. Be the first to start the discussion!