A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can A alone complete the work? MCQ with Answer and Explanation
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Question #1
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A can finish a work in 15 days and B in 20 days. They work together for 6 days and then B leaves. In how many days will A finish the remaining work?
Correct Answer: Option D
Explanation:
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 6 days, work done = 6 * 7 = 42 units. Remaining work = 60 - 42 = 18 units. Time taken by A to complete remaining work = 18 / 4 = 4.5 days.
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 6 days, work done = 6 * 7 = 42 units. Remaining work = 60 - 42 = 18 units. Time taken by A to complete remaining work = 18 / 4 = 4.5 days.
This question belongs to:
Maths
Time and Work
Question #2
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A can complete a work in 10 days and B in 27 days. If they work together, the work will be completed in:
Correct Answer: Option D
Explanation:
Combined rate = 1/10 + 1/27. Required time = 7.3 days.
Combined rate = 1/10 + 1/27. Required time = 7.3 days.
This question belongs to:
Maths
Time and Work
Question #3
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A work could be completed in 100 days by some workers. However, due to the absence of 10 workers, it was completed in 110 days. Find the original number of workers.
Correct Answer: Option C
Explanation:
Let the original number of workers be x. Using M1 * D1 = M2 * D2: x * 100 = (x - 10) * 110 => 100x = 110x - 1100 => 10x = 1100 => x = 110.
Let the original number of workers be x. Using M1 * D1 = M2 * D2: x * 100 = (x - 10) * 110 => 100x = 110x - 1100 => 10x = 1100 => x = 110.
This question belongs to:
Maths
Time and Work
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