A ball is dropped from a height 'h' and simultaneously another ball is thrown horizontally from the same height. Which ball will hit the ground first? (Neglect air resistance) MCQ with Answer and Explanation
A ball is dropped from a height 'h' and simultaneously another ball is thrown horizontally from the same height. Which ball will hit the ground first? (Neglect air resistance)
A. The dropped ball
B. The horizontally thrown ball
C. Depends on the initial horizontal velocity
D. Both will hit the ground simultaneously
Answer: Option D
Solution (By JKExamLibrary)
Vertical and horizontal motions are completely independent. Both balls have zero initial downward (vertical) velocity and both are subject to the same downward acceleration due to gravity (g). Since the vertical height (h) is the same, using h = ut + ½gt², time t = √(2h/g) applies equally to both. Thus, they hit the ground simultaneously.
Explanation:
At maximum height, vertical velocity = 0 momentarily, but acceleration = g downward throughout motion. Memory tip: 'Peak: v=0, a=g; gravity never switches off'. Kinematics concept frequently tested to correct misconception that acceleration vanishes at peak.
Explanation:
E = mc² = 0.001 kg × (3×10⁸)² = 0.001 × 9×10¹⁶ = 9×10¹³ J. Enormous energy. 1 g mass if fully converted gives this. Atomic bomb converts small fraction.
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