A body is lifted vertically through a height h. The work done against gravity is stored as: MCQ with Answer and Explanation

A body is lifted vertically through a height h. The work done against gravity is stored as:
A. Thermal energy
B. Gravitational potential energy
C. Kinetic energy
D. Elastic potential energy
Answer: Option B
Solution (By JKExamLibrary)
When a body is lifted against gravity, work done (mgh) is stored as gravitational potential energy. This energy can be recovered when the body falls. Kinetic energy relates to motion, thermal to heat, elastic to deformed materials. The conservation of energy principle states that work done against conservative forces becomes potential energy. Formula: PE = mgh, where h is height above reference. Memory aid: 'Potential' means stored energy due to position. This conceptual question tests energy transformation understanding, frequently appearing in work-energy theorem applications in competitive exams.

This question belongs to: Science Physics

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Question #1 Report Error
A particle performs Simple Harmonic Motion (SHM). If its displacement from the mean position is half of its amplitude, the ratio of its kinetic energy to potential energy is:
A. 3:1
B. 1:1
C. 1:3
D. 2:1

Correct Answer: Option A


Explanation:
In SHM, Total Energy (E) = 1/2 k A^2. Potential Energy (U) at displacement x is 1/2 k x^2. Kinetic Energy (K) is E - U = 1/2 k (A^2 - x^2). Given x = A/2. U = 1/2 k (A/2)^2 = 1/2 k (A^2 / 4) = E/4. Since total energy is conserved, K = E - E/4 = 3E/4. The ratio of Kinetic to Potential Energy (K:U) is (3E/4) / (E/4) = 3:1.

This question belongs to: Science Physics
Question #2 Report Error
The phenomenon of splitting of spectral lines in magnetic field is called
A. Raman effect
B. Zeeman effect
C. Stark effect
D. Compton effect

Correct Answer: Option B


Explanation:
Zeeman effect: splitting due to magnetic field. Stark effect due to electric field.

This question belongs to: Science Physics
Question #3 Report Error
An electric bulb rated 220 V, 100 W is operated at 110 V. The power consumed is
A. 100 W
B. 50 W
C. 25 W
D. 12.5 W

Correct Answer: Option C


Explanation:
Resistance R = V²/P = 220²/100 = 484 Ω. At 110 V, P = V²/R = 110²/484 = 12100/484 = 25 W. Assuming resistance constant. Power reduces to quarter when voltage halved (P ∝ V² for fixed R).

This question belongs to: Science Physics