A bullet of mass 20 g is fired with velocity 200 m/s. Its momentum is MCQ with Answer and Explanation

Explanation:
The height of capillary rise is given by Jurin's law: h = 2Tcos(theta) / (rrhog). In a freely falling elevator, the effective acceleration due to gravity (g') is zero (weightlessness). As effective g approaches zero, the theoretical height h approaches infinity. In reality, the water will rise to the very top of the tube, regardless of its length, but will not overflow.

Explanation:
PE = mgh, so directly proportional to height h. If h becomes 2h, PE becomes 2 × 100 = 200 J, assuming g constant. For large heights, g varies, but basic assumption. Thus 200 J.

Explanation:
K = p²/(2m) => 100 = 2500/(2m) => m = 2500/200 = 12.5 kg.