Potential energy of a body at a height h is 100 J. If height is doubled, the potential energy becomes MCQ with Answer and Explanation
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Question #1
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The dimensional formula of torque is the same as that of:
Correct Answer: Option B
Explanation:
Torque τ = r × F, so dimensions [L][MLT⁻²] = [ML²T⁻²]. Work W = F·d, dimensions [MLT⁻²][L] = [ML²T⁻²], identical. Momentum is [MLT⁻¹], force [MLT⁻²], power [ML²T⁻³]. Though torque and work have same dimensions, they are physically distinct: torque is vector (rotational effect), work is scalar (energy transfer). Memory tip: 'Torque and work share [ML²T⁻²]; but torque = rF sinθ, work = Fd cosθ'. This dimensional analysis question tests ability to compare quantities, frequently appearing in competitive exams. Always verify dimensions but remember physical context differs.
Torque τ = r × F, so dimensions [L][MLT⁻²] = [ML²T⁻²]. Work W = F·d, dimensions [MLT⁻²][L] = [ML²T⁻²], identical. Momentum is [MLT⁻¹], force [MLT⁻²], power [ML²T⁻³]. Though torque and work have same dimensions, they are physically distinct: torque is vector (rotational effect), work is scalar (energy transfer). Memory tip: 'Torque and work share [ML²T⁻²]; but torque = rF sinθ, work = Fd cosθ'. This dimensional analysis question tests ability to compare quantities, frequently appearing in competitive exams. Always verify dimensions but remember physical context differs.
Question #2
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Myopia is corrected by
Question #3
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The buoyant force on an object immersed in a fluid depends on
Correct Answer: Option C
Explanation:
Buoyant force = weight of displaced fluid = ρ_fluid × V_displaced × g. Independent of depth (if fluid incompressible) and object's density, though object density determines if it floats. Shape affects volume displaced when floating.
Buoyant force = weight of displaced fluid = ρ_fluid × V_displaced × g. Independent of depth (if fluid incompressible) and object's density, though object density determines if it floats. Shape affects volume displaced when floating.
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