A can complete a work in 11 days and B in 14 days. If they work together, the work will be completed in: MCQ with Answer and Explanation
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Question #1
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If 10 men can complete a project in 12 days, how many more men are required to finish it in 8 days?
Correct Answer: Option D
Explanation:
Using M1 * D1 = M2 * D2: 10 * 12 = M2 * 8 => 120 = 8 * M2 => M2 = 15 men. More men required = 15 - 10 = 5.
Using M1 * D1 = M2 * D2: 10 * 12 = M2 * 8 => 120 = 8 * M2 => M2 = 15 men. More men required = 15 - 10 = 5.
This question belongs to:
Maths
Time and Work
Question #2
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A can complete a work in 20 days and B in 30 days. They start together but A leaves after 4 days. In how many total days will the work be completed?
Correct Answer: Option D
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. In 4 days, work completed = 4 * (3 + 2) = 20 units. Remaining work = 60 - 20 = 40 units. Time taken by B to finish remaining work = 40 / 2 = 20 days. Total days = 4 + 20 = 24 days.
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. In 4 days, work completed = 4 * (3 + 2) = 20 units. Remaining work = 60 - 20 = 40 units. Time taken by B to finish remaining work = 40 / 2 = 20 days. Total days = 4 + 20 = 24 days.
This question belongs to:
Maths
Time and Work
Question #3
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A can do a piece of work in 20 days and B in 30 days. They work together for 7 days and then both leave. Then C alone finishes the remaining work in 10 days. In how many days can C alone finish the full work?
Correct Answer: Option C
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 7 days, work done = 7 * 5 = 35 units. Remaining work = 60 - 35 = 25 units. C takes 10 days to do 25 units, so efficiency of C = 25 / 10 = 2.5 units/day. Time taken by C for full work = 60 / 2.5 = 24 days.
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 7 days, work done = 7 * 5 = 35 units. Remaining work = 60 - 35 = 25 units. C takes 10 days to do 25 units, so efficiency of C = 25 / 10 = 2.5 units/day. Time taken by C for full work = 60 / 2.5 = 24 days.
This question belongs to:
Maths
Time and Work
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