A can complete a work in 23 days and B in 28 days. If both work together, in how many days will the work be completed? MCQ with Answer and Explanation
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Question #1
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A and B work together. A alone can complete the work in 18 days and B alone in 34 days. What percentage of the total daily work is contributed by A?
Correct Answer: Option D
Explanation:
A share = (1/18) / (1/18+1/34) ×100 = 65.38%.
A share = (1/18) / (1/18+1/34) ×100 = 65.38%.
This question belongs to:
Maths
Time and Work
Question #2
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23 men can complete a work in 30 days. If 28 men work at the same rate, the work will be completed in:
Correct Answer: Option C
Explanation:
Total work = 690 man-days. Time = 690/28 = 24.64 days.
Total work = 690 man-days. Time = 690/28 = 24.64 days.
This question belongs to:
Maths
Time and Work
Question #3
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A and B can complete a piece of work in 12 and 18 days respectively. They begin the work together, but A leaves 4 days before the completion of the work. For how many days did A and B work together?
Correct Answer: Option B
Explanation:
Total work = LCM(12, 18) = 36 units. Efficiency of A = 3, B = 2. Let total days be x. B works for x days, A works for (x - 4) days. 3(x - 4) + 2x = 36 => 3x - 12 + 2x = 36 => 5x = 48 => x = 9.6 days. A and B worked together for x - 4 = 9.6 - 4 = 5.6 days.
Total work = LCM(12, 18) = 36 units. Efficiency of A = 3, B = 2. Let total days be x. B works for x days, A works for (x - 4) days. 3(x - 4) + 2x = 36 => 3x - 12 + 2x = 36 => 5x = 48 => x = 9.6 days. A and B worked together for x - 4 = 9.6 - 4 = 5.6 days.
This question belongs to:
Maths
Time and Work
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