A can do a piece of work in 15 days and B in 20 days. They began the work together but A left after 4 days. In how many days will B complete the remaining work? MCQ with Answer and Explanation

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A can do a piece of work in 15 days and B in 20 days. They began the work together but A left after 4 days. In how many days will B complete the remaining work?

A. 8 days

B. 10(1/3) days

C. 9(1/3) days

D. 10(2/3) days

Answer: Option D

Solution (By JKExamLibrary)

Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 4 days, work completed = 4 * 7 = 28 units. Remaining work = 60 - 28 = 32 units. Time taken by B to complete remaining work = 32 / 3 = 10(2/3) days.

This question belongs to: Maths Time and Work

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Question #1 Report Error

A and B can do a piece of work in 45 and 40 days respectively. They began the work together, but A left after some days and B finished the remaining work in 23 days. After how many days did A leave?

A. 6 days

B. 8 days

C. 9 days

D. 12 days

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Correct Answer: Option C

Explanation:
Total work = LCM(45, 40) = 360 units. Efficiency of A = 8, B = 9. B worked alone for 23 days: work done = 23 * 9 = 207 units. Remaining work = 360 - 207 = 153 units. This was done by A and B together. Combined efficiency = 8 + 9 = 17. Number of days they worked together = 153 / 17 = 9 days. Thus, A left after 9 days.

This question belongs to: Maths Time and Work